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(4x)^2=484
We move all terms to the left:
(4x)^2-(484)=0
a = 4; b = 0; c = -484;
Δ = b2-4ac
Δ = 02-4·4·(-484)
Δ = 7744
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{7744}=88$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-88}{2*4}=\frac{-88}{8} =-11 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+88}{2*4}=\frac{88}{8} =11 $
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